Question #5d6a0

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Question #5d6a0

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Answer 1 · 2017-10-27T05:58:00

$x = 4, 6$ $x = 4,6$

Explanation:

The y-intercept $(0, y)$ $(0, y)$ is when $x = 0$ $x=0$ . The x-intercept $(x, 0)$ $(x,0)$ is when $y = 0$ $y=0$ . So to find the x-intercept we will set $y = f (x)$ $y = f(x)$ to $0$ $0$ and solve for $x$ $x$ .
$f (x) = - 3 {(x - 5)}^{2} + 3$ $f(x)=-3(x-5)^2+3$
$0 = - 3 {(x - 5)}^{2} + 3$ $0=-3(x-5)^2+3$
$0 = - 3 (x^{2} - 10 x + 25) + 3$ $0=-3(x^2-10x+25)+3$
$0 = - 3 x^{2} + 30 x - 75 + 3$ $0=-3x^2+30x-75+3$
$0 = - 3 x^{2} + 30 x - 72$ $0=-3x^2+30x-72$
$0 = - 3 (x^{2} - 10 x + 24)$ $0=-3(x^2-10x+24)$
$0 = - 3 (x - 6) (x - 4)$ $0=-3(x-6)(x-4)$

$x - 6 = 0$ $x-6=0$
$x = 6$ $x=6$

$x - 4 = 0$ $x-4=0$
$x = 4$ $x=4$

so $x = 4, 6$ $x = 4,6$
You should also double-check your answers by plugging the values back into the original question. Sometimes the answers you get can be erroneous.

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Question #5d6a0

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