Question #a0de1

2 Answers
Oct 3, 2017

See the answer below...

Explanation:

The wheel with a diameter of #30 #inch overcomes a distance of (#pixx#diameter#xx#n revolutions)=#pixx30xx240=7200pi# inch

In this case the second wheel will also overcome a same distance i.e, #7200pi# inch.
The diameter of the second wheel is #20# inch hence its circumference will be #20xxpi=20pi# inch.

So the second wheel will have to complete #(7200pi)/(20pi)=360# revolutions...

Hope it helps...
Thank you...

Oct 28, 2017

The small wheel will revolve 360 times in the same distance.

Explanation:

These two wheels may be on one side of a wagon with the front steering wheels smaller than the load carrying wheels at the back.

Then in the same distance:

The #30i# wheel turns #240# times for a distance of #30i(240)#.
The #20i# wheel turns #T# times for a distance of #20i(T) .

And: #(30i)(240)=20iT#

#720canceli=20canceliT#

#360=T#