Question

Question #038ea

Answer 1

There's no trick, just follow the rules

Explanation:

`(x^2+y^2-z^2-2xy)/(x^2-y^2+z^2-2xz)`

`=(x^2-2xy+y^2-z^2)/(x^2-2xz+z^2- y^2)`

`=((x-y)^2-z^2)/((x-z)^2- y^2)`

`=(((x-y)-z)((x-y)+z))/(((x-z)- y)(x-z+ y))`

`=((x-y-z)(x-y+z))/((x-y- z)(x+ y-z))`

`=(x-y+z)/(x+ y-z)`