How do you simplify (1/9)^(-3/2)(19)32?

1 Answer
Oct 28, 2017

Using the formula a ^ (-b) = (1 / a^b)ab=(1ab), and the formula (a ^ m) ^ n = a ^ (mn)(am)n=amn, we obtain answer is 27.

Explanation:

We have, in our problem,

(1/9) ^ (-3/2)(19)32 ( Expression 1 )

Rewrite the BASE (1/9)(19) in our ( Expression 1 ), using the formula a ^ (-b) = (1 / a^b)ab=(1ab), as

(3 ^ (-2)) ^ (-3/2)(32)32 ( Expression 2 )

--------------- Observe that 3 ^ 232 is 9 and 3 ^(-2) 32 is 1/919 ----------------

Using the formula (a ^ m) ^ n = a ^ (mn)(am)n=amn, we can rewrite our ( Expression 2 ) as

3 ^ ((-2)*(-3/2))3(2)(32)

Simplify by multiplying (-2) by (-3/2) in the Exponent. We get, 3.

Hence, our ( Expression 2 ) can be written as

3 ^ 333

Which gives us 27.

Hence, ( Expression 1 ) when simplified yields 27.