Question #d3517

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Question #d3517

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Answer 1 · 2017-10-29T08:06:02

$y = (\frac{3}{4}) x + 1$ $y=(3/4)x+1$

Explanation:

The slope between two points $(x_{1}, y_{1}) & (x_{2}, y_{2})$ $(x_1, y_1) & (x_2, y_2)$ is:
$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$ => thus in this case the slope between
$(4, 4) & (- 4, - 2)$ $(4, 4) & (-4, -2)$ is:
$m = \frac{- 2 - 4}{- 4 - 4} = \frac{- 6}{- 8} = \frac{3}{4}$ $m=(-2-4)/(-4-4)=(-6)/(-8)=3/4$
using point slope formula:
$y - y_{1} = m (x - x_{1})$ $y-y_1=m(x-x_1)$ , we get:
$y - 4 = \frac{3}{4} (x - 4)$ $y - 4=3/4(x-4)$ , expand and simplify:
$y = (\frac{3}{4}) x + 1$ $y=(3/4)x+1$ => equation in slope-intercept form

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