Question #a46f1

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Answer 1 · 2017-10-30T13:51:41

$"please look at the solution below."$

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The electric potential is a scalar quantity.
Electric charges are regularly distributed to the outer surface of the sphere.
When the solution is being made, it is assumed that the electric charge is collected at the center of the sphere.
Every point in the sphere has the same electric potential.
the electric potential of any point on the sphere is equal to the electric potential of any point within the sphere.
The electric potential of any point within sphere is maximum.
r is the radius of the sphere, d is the distance from the center of the sphere.
As you move away from the center of the globe, the electric potential decreases.

$" if d< r "=>V=k*(q)/(r)$

$" if d=r "=>V=k*(q)/r$

$" if d>r "=> V=k*(q)/(d)$

$"solution to the problem:"$

$q=20C$
$r=0.50m$
$k=9.10^9$

$"if d=0.50m :"$

$V=k*(20)/(0.50)=40k=40*9*10^9=360*10^9=3.6*10^(11) V.$

$"if d=0.80m :"$

$V=k*(20)/(0.80)=25k=25*9*10^9=225*10^(9)=2.25*10^(11)V.$