Question

How do you solve `x=\frac{5}{2}\times (1,8\times 10^{23})\times (x-330)`?

Answer 1

The short answer is `x=330`

Explanation:

`x=5/2×(1.8×10^23)xx(x−330)`

1)You can start to the simple calculation:

`x=4.5×10^23xx(x−330)`

2)4.5×10^23 is a huge number, let's replace it by A:

`x=A(x−330)`

3) Isolating the `x`s:

`(1-A)x=-330A`

`x=330((-A)/(1-A))`

4)`A` is so big that `((-A)/(1-A))` is infinitesimally equal to 1, therefore,

`x=330`

5)Nevertheless, let's try to calculate the "right answer"

`((-A)/(1-A))=A/(A-1)=(A-1)/(A-1)+1/(A-1)~~1+1/A=1+1/(4.5xx10^23)=`

`1+(2/9)xx10^-23`

No computer can handle with 23 digits numbers. so we have to continue like this:

`x=330((-A)/(1-A))~~330(1+(2/9)xx10^-23)`

`x=330+330xx(2/9)xx10^-23`=330+73.333xx10^-23#

Now we get the ridiculous number of :

`330.000000000000000000000733`