Question #78f69
2 Answers
Nov 2, 2017
Explanation:
#6x^2+5x-6=0" is in standard form"#
#"that is "ax^2+bx+c color(white)(x);a!=0#
#"to factorise consider the factors of ac which sum to b"#
#"the factors of - 36 which sum to + 5 are + 9 and - 4"#
#6x^2+9x-4x-6=0larrcolor(blue)"split the middle term"#
#"factorise by 'grouping'"#
#rArr(2x+3)(color(red)(3x-2))=0#
#"equate each factor to zero and solve for x"#
#2x+3=0rArrx=-3/2#
#3x-2=0rArrx=2/3#
Explanation:
Therefore, each factor set equal to
Therefore, the roots are
In the quadratic equation curve of
Hence, their coordinates are