How do you solve 5=(u+6)/5 + (5u-2)/65=u+65+5u−26?

1 Answer
Yiu A.
Nov 2, 2017

u=4

Explanation:

First, since there are fractions in this question, we can find the common denominator and group the fractions together, which is easier for us to do the question.

5=(u+6)/5+(5u-2)/65=u+65+5u−26
5=[(u+6)*6]/(5*6)+[(5u-2)*5]/(6*5)5=(u+6)⋅65⋅6+(5u−2)⋅56⋅5
5=(u*6+6*6)/30+(5u*5-2*5)/305=u⋅6+6⋅630+5u⋅5−2⋅530
5=(6u+36+25u-10)/305=6u+36+25u−1030

Then, we can multiply by 30 on both sides to eliminate the denominator.

5*30=(6u+36+25u-10)/30*305⋅30=6u+36+25u−1030⋅30
150=26+31u150=26+31u
124=31u124=31u
u=124/31=4u=12431=4

Here is the answer. Hope this can help you :)

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