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Determine the energy of a photon whose frequency is 5.28 × 1017 Hz?

1 Answer

Nov 2, 2017

$E = 3.50 \times 10^{16}$ $E = 3.50 xx 10^(16)$ J

Explanation:

The formula for determining the energy of a photon is $E = h f$ $E = hf$ , where

E is energy of the photon
h is planck's constant ( $6.63 \times 10^{- 34}$ $6.63 xx 10^(-34)$ )
f is the lights frequency

So substitute the values into the equation.

$E = (6.63 \times 10^{- 34}) (5.28 \times 10^{17}$ $E =(6.63xx10^(-34))(5.28xx10^17$ Hz $)$ $)$
$E = 3.50 \times 10^{16}$ $E = 3.50 xx 10^(16)$ J

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