Question

Question #a9c10

Answer 1

7.250 kilo calories

Explanation:

Heat required to raise the temperature of ice from -10°C to 0°C `=Q_1`
Heat required to convert ice at 0°C to water at 0°C `=mL_("fusion")`
Heat required to raise temperature of water at 0°C to 100°C `=Q_2`
Heat required to convert water at 100°C to steam at 100°C `=mL_(vapour)`

Total heat required `=Q_1 + mL_(fusion) + Q_2 + mL_(vapour)`

`=mS_(ice)dT + mL_(fusion) + mS_(water)dT’ + mL_(vapour)`

`= (10g × (0.5 cal)/(g°C) xx (0 - (-10)°C)) + (10g × (80 cal)/(g)) + (10g × (1 cal)/(g°C) × (100 - 0)°C) + (10g × (540 cal)/(g°C))`

`= 50 cal + 800 cal + 1000 cal + 5400 cal`

`= 7250 cal`

`= 7.25 kcal`