Question

Question #7fb40

Answer 1

18.00 m/s

Explanation:

Temperature at STP `= 0°C = 273 K`

Gas constant `R = 8.314 J/(mol K)`

Average velocity `=sqrt((2RT)/M) = sqrt((2 × 8.314 × 273) / 14) ms^-1 = 18.00 ms^-1`