What is the enthalpy of reaction at "373 K" if the heat capacities are the same at "273 K" and we know DeltaH_(rxn) at "273 K"?

2 Answers
Nov 5, 2017

A) -20kJ

Explanation:

Enthalpy of a reaction is NOT affected by the temperature. The temperature may affect the reaction rate , but the inherent amount of heat energy produced or consumed by a reaction remains the same no matter what the conditions of the reaction environment are.

Ref:
https://cbc-wb01x.chemistry.ohio-state.edu/~woodward/ch121/ch5_enthalpy.htm

https://chem.libretexts.org/Core/Physical_and_Theoretical_Chemistry/Thermodynamics/State_Functions/Enthalpy/Heat_of_Reaction

Nov 5, 2017

Due to the assumption of the question that C_P is equal between both the products and reactants at any given temperature, ONLY THEN can we say that DeltaH_"rxn" did not change in that temperature range.

Otherwise, there is a small difference. Remember, this is just Hess's Law...

DeltaH_("rxn","373 K") = DeltaH_("rxn,273 K") + cancel(int_(273)^(373) DeltaC_(P,"rxn")(T)dT)^(~~ 0)

if C_(P("Products"))(T) = C_(P("Reactants"))(T) for both temperatures.

See here for further discussion:
https://chemistry.stackexchange.com/questions/35756/calculating-enthalpy-changes-at-different-temperatures

And see here for further references to back up this answer.


We can write a thermodynamic cycle for that.

  • State 1: Reactants at "273 K"
  • State 2: Products at "273 K"
  • State 3: Reactants at "373 K"
  • State 4: Products at "373 K"

"State 1" stackrel(DeltaH_("rxn","273 K")" ")(->) "State 2"

"State 3" stackrel(DeltaH_("rxn","373 K")" ")(->) "State 4"

"State 1" stackrel(int_(273)^(373) C_(P("reactants"))(T)dT" ")(->) "State 3"

"State 2" stackrel(int_(273)^(373) C_(P("products"))(T)dT" ")(->) "State 4"

We know the first one, and in principle can determine the last two, but do not know the second one. If we want to go from 3 to 4, we can pick the path as follows:

"Reactants at 373 K" -> "Reactants at 273 K" -> "Products at 273 K" -> "Products at 373 K"

This path is then going to result in calculating DeltaH_"rxn" for the reaction at "373 K":

color(blue)(DeltaH_("rxn","373 K")) = -int_(273)^(373) C_(P("reactants"))(T)dT + DeltaH_("rxn,273 K") + int_(273)^(373) C_(P("products"))(T)dT

= color(blue)(barul(|stackrel(" ")(" "DeltaH_("rxn,273 K") + int_(273)^(373) DeltaC_(P,"rxn")(T)dT" ")|))

[See here; this person quotes the same equation I just derived.](https://chemistry.stackexchange.com/questions/35756/calculating-enthalpy-changes-at-different-temperatures) The astute chemist would recognize that this is just Hess's Law.

In other words, we can calculate DeltaH_"rxn" at "373 K" by cooling the reactants from "373 K" to "273 K", using DeltaH_"rxn" at "273 K", and then heating the products back up to "373 K".

NOTE: It is ultimately not entirely clear what the question means by "the heat capacities are the same".

Are we saying

  • C_(P("Reactants"))(T) ~~ C_(P("Products"))(T)?
  • C_(P("Reactants/Products"))("273 K") ~~ C_(P("Reactants/Products"))("373 K")?

I interpret it is meaning that the products and reactants each have the same heat capacities at a particular temperature*, and not*** that they are constant in the temperature range irrespective of what they are in relation to each other.

In that special case,

int_(273)^(373) C_(P("products"))(T)dT-int_(273)^(373) C_(P("reactants"))(T)dT

= int_(273)^(373) DeltaC_(P,"rxn")dT ~~ 0

since the integral of DeltaC_(P,"rxn") ~~ 0 is zero. Only then is DeltaH_("rxn", "373 K") = DeltaH_("rxn", "273 K").

If the question means that C_(P("Reactants"))("373 K") ~~ C_(P("Reactants"))("273 K") and that C_(P("Products"))("373 K") ~~ C_(P("Products"))("273 K"), but that C_(P("Products")) ne C_(P("Reactants")) in general, then we really do NOT have the same DeltaH_"rxn" at two different temperatures:

C_(P("products"))int_(273)^(373) dT - C_(P("reactants"))int_(273)^(373) dT

= DeltaC_(P,"rxn") int_(273)^(373) dT

= color(red)(DeltaC_(P,"rxn") cdot DeltaT ne 0) in general