What is the enthalpy of reaction at "373 K" if the heat capacities are the same at "273 K" and we know DeltaH_(rxn) at "273 K"?
2 Answers
A) -20kJ
Explanation:
Enthalpy of a reaction is NOT affected by the temperature. The temperature may affect the reaction rate , but the inherent amount of heat energy produced or consumed by a reaction remains the same no matter what the conditions of the reaction environment are.
Ref:
https://cbc-wb01x.chemistry.ohio-state.edu/~woodward/ch121/ch5_enthalpy.htm
Due to the assumption of the question that
Otherwise, there is a small difference. Remember, this is just Hess's Law...
DeltaH_("rxn","373 K") = DeltaH_("rxn,273 K") + cancel(int_(273)^(373) DeltaC_(P,"rxn")(T)dT)^(~~ 0)
if
See here for further discussion:
https://chemistry.stackexchange.com/questions/35756/calculating-enthalpy-changes-at-different-temperatures
And see here for further references to back up this answer.
-
https://www.et.byu.edu/~rowley/ChEn273/Topics/Energy_Balances/Reacting_Systems/Heat_of_Rxn_at_other_Temp.htm
(boxed equation) -
https://www.slideshare.net/mobile/mosamgpatel/temperature-effect-on-heat-of-reaction
(Eq. 7)
We can write a thermodynamic cycle for that.
- State 1: Reactants at
"273 K" - State 2: Products at
"273 K" - State 3: Reactants at
"373 K" - State 4: Products at
"373 K"
"State 1" stackrel(DeltaH_("rxn","273 K")" ")(->) "State 2"
"State 3" stackrel(DeltaH_("rxn","373 K")" ")(->) "State 4"
"State 1" stackrel(int_(273)^(373) C_(P("reactants"))(T)dT" ")(->) "State 3"
"State 2" stackrel(int_(273)^(373) C_(P("products"))(T)dT" ")(->) "State 4"
We know the first one, and in principle can determine the last two, but do not know the second one. If we want to go from
"Reactants at 373 K" -> "Reactants at 273 K" -> "Products at 273 K" -> "Products at 373 K"
This path is then going to result in calculating
color(blue)(DeltaH_("rxn","373 K")) = -int_(273)^(373) C_(P("reactants"))(T)dT + DeltaH_("rxn,273 K") + int_(273)^(373) C_(P("products"))(T)dT
= color(blue)(barul(|stackrel(" ")(" "DeltaH_("rxn,273 K") + int_(273)^(373) DeltaC_(P,"rxn")(T)dT" ")|))
[See here; this person quotes the same equation I just derived.](https://chemistry.stackexchange.com/questions/35756/calculating-enthalpy-changes-at-different-temperatures) The astute chemist would recognize that this is just Hess's Law.
In other words, we can calculate
NOTE: It is ultimately not entirely clear what the question means by "the heat capacities are the same".
Are we saying
C_(P("Reactants"))(T) ~~ C_(P("Products"))(T) ?C_(P("Reactants/Products"))("273 K") ~~ C_(P("Reactants/Products"))("373 K") ?
I interpret it is meaning that the products and reactants each have the same heat capacities at a particular temperature*, and not*** that they are constant in the temperature range irrespective of what they are in relation to each other.
In that special case,
int_(273)^(373) C_(P("products"))(T)dT-int_(273)^(373) C_(P("reactants"))(T)dT
= int_(273)^(373) DeltaC_(P,"rxn")dT ~~ 0 since the integral of
DeltaC_(P,"rxn") ~~ 0 is zero. Only then isDeltaH_("rxn", "373 K") = DeltaH_("rxn", "273 K") .
If the question means that
C_(P("products"))int_(273)^(373) dT - C_(P("reactants"))int_(273)^(373) dT
= DeltaC_(P,"rxn") int_(273)^(373) dT
= color(red)(DeltaC_(P,"rxn") cdot DeltaT ne 0) in general