How do you solve #-128= - 8( 8n + 8)#?

1 Answer
Nov 5, 2017

#n = 1#

Explanation:

Distribute #-8(8n+8)# first.
#-128 = -8(8n + 8)#
#-128 = (-8*8n) + (-8*8)#
#-128 = -64n - 64#
Then add 64 to both sides of the equation.
#-128 + 64 = -64n - 64 + 64#
#-64 = -64n#
Now, divide both sides with -64.
#(-64)/-64 = (-64n)/-64#
#1 = n#
So the answer is #n = 1#.

The rule for these kinds of equations is first, you have to simplify each individual side of the equation. Then, when you are simplifying both sides together, you can use PEMDAS without Parenthesis (Exponents, Multiplication, Division, Addition, and Subtraction) except you do it backwards, so you would start simplifying addition and subtraction first.