Question #22517

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Answer 1 · 2017-11-06T02:30:38

$15 m, 10 m$ $15m, 10m$

Let
$l$ $l$ = the length od the garden
$\frac{2}{3} l$ $2/3l$ = the width of the garden

P= 2length + 2width = 50

$50 = 2 l + 2 (\frac{2}{3} l)$ $50= 2l+2(2/3l)$

Simplifying further,
$50 = 2 l + \frac{4}{3} l$ $50=2l+4/3l$
$50 = \frac{10}{3} l$ $50=10/3l$
$l = 15$ $l=15$

$w i d t h = \frac{2}{3} l$ $width=2/3l$
$w i d t h = \frac{2}{3} \cdot 15$ $width=2/3*15$
$w i d t h = 10$ $width=10$

Answer 2 · 2017-11-06T02:31:23

Length = 15 metres
Width = 10 metres

Perimeter of rectangle $= 2 (l + b)$ $= 2(l + b)$

$50 m = 2 (l + b)$ $50 m = 2(l + b)$ ……[1]

$50 m = 2 (l + \frac{2}{3} l)$ $50 m = 2(l + 2/3l)$

$50 m = \frac{10 l}{3}$ $50 m = (10l)/3$

$l = 15 m$ $l = 15 m$

Substitute $l = 15 m$ $l=15m$ in equation [1]

$50 m = 2 (15 + b)$ $50 m = 2(15 + b)$

$\frac{50}{2} m = 15 + b$ $50/2m = 15 + b$

$b = 10 m$ $b = 10m$