Question #0ee53

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Question #0ee53

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Answer 1 · 2017-11-08T06:47:04

$6059.3 m s^{- 1}$ $6059.3 ms^-1$

Explanation:

Oribatal radius (R) $= 4500 k m + 6400 k m = 10900 k m$ $= 4500 km + 6400km = 10900 km$

Orbital speed $= \sqrt{\frac{G M}{R}} = \sqrt{\frac{6.67 \times 10^{- 11} \times 6 \times 10^{24}}{10900 \times 10^{3}}} m s^{- 1} = 6059.3 m s^{- 1}$ $= sqrt((GM)/R) = sqrt((6.67 × 10^-11 × 6 × 10^24)/(10900 × 10^3)) ms^-1 = 6059.3 ms^-1$

Speed of satellite is independent of its mass.

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Question #0ee53

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