How do you solve this system of equations: #x- 0.2y = 0 and 4x - 8y = - 4#?

1 Answer
flaxar
Nov 8, 2017

#x# = #1/9# , #y# = #5/9#

Explanation:

#x-0.2y=0# ---- 1

#4x-8y=-4# ---- 2

from equation 1,
#x=0.2y#

substitute #x=0.2y# into equation 2
#4(0.2y)-8y=-4#
#0.8y-8y=-4#
#-7.2y=-4#
#y=5/9#

substitute #y=5/9# into #x=0.2y#
#x=0.2(5/9)#
#x=1/9#

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