What is the equation of the line that has a slope of $\frac{4}{7}$ $4/7$ and passes through (1, 3)?

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Answer 1 · 2017-11-09T03:10:31

$y = \frac{4}{7} x + \frac{17}{7}$ $y = 4/7x + 17/7$

Slope (m) $= \frac{4}{7}$ $=4/7$

$(x, y) = (1, 3)$ $(x,y) = (1,3)$

$x = 1$ $x = 1$

$y = 3$ $y = 3$

$y = m x + c$ $y = mx + c$

$3 = (\frac{4}{7} \times 1) + c$ $3 = (4/7xx1) + c$

$c = 3 - \frac{4}{7}$ $c = 3 - 4/7$

$c = (3 \times \frac{7}{7}) - \frac{4}{7}$ $c = (3 × 7/7) - 4/7$

$c = \frac{21}{7} - \frac{4}{7}$ $c = 21/7 - 4/7$

$c = \frac{21 - 4}{7}$ $c = (21 - 4)/7$

$c = \frac{17}{7}$ $c = 17/7$

∴ $Equation of line is$ $"Equation of line is"$ $y = \frac{4}{7} x + \frac{17}{7}$ $y= 4/7x + 17/7$

Answer 2 · 2017-11-09T03:13:54

$y = (\frac{4}{7}) x + (\frac{17}{7})$ $y = (4/7)x + (17/7)$

Format of equation with slope and coordinates of one point is
$(y - y_{1}) = m (x - x_{1}$ $(y-y_1) = m (x-x_1$

Given $x_{1} = 1, y_{1} = 3$ $x_1=1, y_1=3$ & $m = \frac{4}{7}$ $m=4/7$

$y - 3 = (\frac{4}{7}) (x - 1)$ $y - 3 = (4/7) (x- 1)$

$7 y - 21 = 4 x - 4$ $7y-21 = 4x-4$

$7 y = 4 x + 17$ $7y = 4x + 17$

$y = (\frac{4}{7}) x + (\frac{17}{7})$ $y = (4/7)x + (17/7)$

What is the equation of the line that has a slope of 474/7 and passes through (1, 3)?