How do you differentiate #f(x) = tanx+cscx#? Calculus Basic Differentiation Rules Power Rule 1 Answer Anthony R. Nov 9, 2017 #f'(x)=sec^2x-cscxcotx# Explanation: Take each individual derivative, then combine #d/dx(tanx)=sec^2x# #d/dx(cscx)=-cscxcotx# #:.f'(x)=sec^2x-cscxcotx# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 2902 views around the world You can reuse this answer Creative Commons License