Two point charges are 10.0 cm apart and have charges of 2.0 μC and -2.0 μC, respectively. What is the magnitude of the electric field at the midpoint between the two charges?

1 Answer
ali ergin
Nov 9, 2017

please look at the fallowing details.

Explanation:

  • Every electric charge has a electric field.
  • The charges in the electric field are affected each other.
  • As you move away from the electric charge, the intensity of the electric field decreases.
  • The electric field is a vector quantity.
  • The electric field of each charge is calculated to find the intensity of the electric field at a point.
  • The vectorial sum of the vectors are found.
  • The electric field of the positive charge is directed outward from the charge.

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  • the electric field of the negative charge is directed towards the charge.

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  • we can draw this pattern for your problem.

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let the electric field of charge +2 μC be E1 (red vector)

d=5cm=5.10−2m
q1=+2μC=+2⋅10−6C

  • The electric field of a charge is calculated by formula :

E=k.qd2

E1=k⋅2.10−65.10−2=+k⋅0.4⋅10−4NC

E2=k⋅−2.10−65.10−2=−k⋅0.4⋅10−4NC

  • The electric field of the charges at the point C is EC

EC=E1+E2

EC=k⋅0.4⋅10−4+k⋅0.4⋅10−4

E=2⋅k⋅0.4⋅10−4=0.8⋅k⋅10−4

k=9.109

EC=0.8⋅9.109⋅10−4

EC=7.2⋅105NC

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