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Question #6ce93

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Dani W. · Darshan Senthil

Nov 10, 2017

$x^{2} - 5 x - 10 - \frac{56}{x - 2}$ $x^2-5x-10 - 56/(x-2)$

Explanation:

I recommend using synthetic division.

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$\frac{x^{3} - 7 x^{2} - 36}{x - 2} = x^{2} - 5 x - 10$ $(x^3-7x^2-36)/(x-2)=x^2-5x-10$ with a remainder of -56. This expression would be written as:

$x^{2} - 5 x - 10 - \frac{56}{x - 2}$ $x^2-5x-10 - 56/(x-2)$

This just signifies that while the rest of the polynomial divided out, this one piece didn't.

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