An object with a mass of 3 kg3kg is traveling in a circular path of a radius of 6 m6m. If the object's angular velocity changes from 6 Hz6Hz to 17 Hz17Hz in 5 s5s, what torque was applied to the object?

1 Answer
Nov 11, 2017

"1492.8 Nm"1492.8 Nm of Torque was applied to the object.

Explanation:

Torque is rate of change of angular momentum.

T = (I(omega_f - ω_i))/t

= (I2pi(f_f - f_i))/t

= (mr^2 2pi(f_f - f_i))/t

= ("3 kg × (6 m)"^2 × 2 π (17 - 6) "Hz")/"5 s" = "1492.8 Nm"