How do you solve $x^{2} - 10 x = - 11$ $x^2-10x=-11$ by completing the square?

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Answer 1 · 2017-11-14T00:38:29

$x^{2} - 10 x = - 11$ $x^2 - 10x = -11$

Add 11 to both sides

$x^{2} - 10 x + 11 = 0$ $x^2 - 10x + 11 = 0$

Divide -10 by 2 to see the plus number or minus number after the x (you'll see)

You get -5

What is -5 squared?

25

Add 14 to both sides of the equation to get 25

$x^{2} - 10 x + 25 = 14$ $x^2 - 10x + 25 = 14$

You get

${(x - 5)}^{2} = 14$ $(x-5)^2 = 14$

Root both sides

x-5 = Root 14, and x-5 = Negative Root 14

Add 5 to both equations to get both solutions

1.26, 8.74 (approximate answers)

How do you solve x^2-10x=-11x2−10x=−11 x^2-10x=-11 by completing the square?