Question

Question #07f4e

Answer 1

`-12,-13,-14`

Explanation:

`(-12)+(-13)+(-14)=-39`
You know you need 3 integers that all have about the same value because they are consecutive, so divide 39 by 3.
`39/3=13`
You can then use 2 integers, one greater and one less than -13, to reach -39

Answer 2

`-12, -13, -14`

Explanation:

Given: three consecutive integers with sum of -39

We know that the integers are consecutive, so let
`x - 1 = 1"st integer"`
`x = 2"nd integer"`
`x + 1 = 3"rd integer"`

Since we know that the sum of the three integers is -39, we know that
`(x - 1) + (x) + (x + 1) = -39`

Solving for this:
`(x - 1) + (x) + (x + 1) = -39`
`x - 1 + x + x + 1 = -39`
`3x = -39`
`x = -13`

In this case, by substituting the computed `x` with the values above, we would know that:
1st integer = -14
2nd integer = -13
3rd integer = -12

*Note that it does not matter if you add positive 1 or negative 1 just as long as you use consistent terms and you define your variables properly. So regardless of whether you use x, x - 1, x - 2 to define your three integers or x, x + 1, x + 2, you will still arrive at the same answer.