How do you solve the system of equations $5 x - 2 y = 36$ $5x - 2y = 36$ and $3 x - 5 y = 33$ $3x - 5y = 33$ ?

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Answer 1 · 2017-11-15T01:46:19

$x \approx - 12.947$ $x approx -12.947$
$y \approx - 50.368$ $y approx -50.368$

Solve first equation for y:

$y = \frac{5 x - 36}{2}$ $y = (5x-36)/2$

Substitute that value of y into the second equation:

$3 x - 5 \cdot \frac{5 x - 36}{2} = 33$ $3x - 5*(5x-36)/2 = 33$

Solve for x:

$x \approx - 12.947$ $x approx -12.947$

Plugin value of x found above into the equation in the first line to find y:

$y = \frac{5 \cdot (- 12.947) - 36}{2} \approx - 50.368$ $y = (5*(-12.947)-36)/2 approx -50.368$

How do you solve the system of equations 5x−2y=365x - 2y = 36 and 3x−5y=333x - 5y = 33?