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Question #7d2f5

1 Answer

Nov 16, 2017

$1/2x+cosx+c$

Explanation:

$int(1/2-sinx )dx$

$=int1/2dx-intsinxdx$ $color(white)(blan)$ using $(intf(x)+g(x)dx=intf(x)dx+intg(x)dx)$

$=1/2x-(-cosx)+c$ $color(white)(blan)$ $(intsinxdx=-cosx+c)$

$=1/2x+cosx+c$

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