How do you find the asymptotes for $f (x ) = (3x^2 - 2x - 1) / (x + 4 )$ ?

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Answer 1 · 2017-11-16T18:03:39

Vertical asymptote $x=-4$

$3x^2-2x-1$
$x_(1,2)=(2+-sqrt(4-4*3*(-1)))/(2*3)=(2+-4)/6$
$=>$
$x_1=1$
$x_2=-1/3$
$=>$
$f_((x))=((x-1)(3x+1))/(x+4)$
$=>$
Vertical asymptote $x=-4$

How do you find the asymptotes for f (x ) = (3x^2 - 2x - 1) / (x + 4 )f (x ) = (3x^2 - 2x - 1) / (x + 4 )?