Question #f107b

Question

699 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-17T17:08:07

See explanation

#y^2-14y+46=0#

Lets identify a, b, and c

#ay^2+by+c=0#
#a=1#
#b=-14#
#c=46#

Plug this into the quadratic formula-
#(-b+-sqrt(b^2-4ac))/(2a)#

#(-(-14)+-sqrt((-14)^2-4(1*46)))/(2(1))#
Now solve
#(14+-sqrt(196-184))/(2)#

#(14+-sqrt(12))/(2)#

#(14+-2sqrt(3))/(2)#

y = 8.73205
y = 5.26794
or
y = #7+sqrt(3)#
y= #7-sqrt(3)#