Work out? The vertical and horizontal component of a fired projectile are 30m/S and 20M/S respectively. What is the magnitude of the velocity after 1.5 second is-------(Take g=10M/S²)? Thanks

1 Answer
Bidesh B.
Nov 18, 2017

#15m/s#

Explanation:

Horizontal component remains constant , So #V_x=20m/s#
Vertical component after t=1.5 s,
#V_y=U_y- g*t=30-10*1.5=15m/s#
So resultant velocity #V=sqrt(V_x^2+V_y^2)=sqrt(400+225)=25m/s#
Direction w.r.t x axis #theta=##tan^-1(15/20)=36.86 degree#

Related questions
Impact of this question
1021 views around the world
You can reuse this answer
Creative Commons License