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Answer 1 · 2017-11-18T11:44:16

This uses the momentum equation, $F.t = m Deltav$ and assumes that force remains constant throughout the interaction.

Incidentally, this equation is just a rearramhDeltangement of Newton’s 2nd law, and we’ll use it in the form $F = m(Delta v)/(Delta t)$

$F = 0.1 xx (50 - 0)/(5 xx 10^-3)$

$F = 1000$ N

Answer 2 · 2017-11-18T11:49:35

Average acceleration $bara=(Deltav)/t$
where $Deltav=$ change in speed, and $t=$ time

$bara=(50.0m//s)/(5.00*10^(-3)s)=1.00*10^4m//s^2$

Since average force $barF=m*bara$

$barF=0.100kg*1.00*10^4m//s^2=1.00*10^3kg*m//s^2=1.00*10^3N$
as $N-=kg*m//s^2$ by definition