How do you factor $45x^2 - 60x +20$ ?

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Answer 1 · 2017-11-18T16:16:17

$5(3x - 2)^2$

$45x^2 - 60x + 20$

First factor out 5 so that you will be left with smaller coefficients
$5(9x^2 - 12x + 4)$

So we know that:

$9 = 3 * 3$
$4 = 2 * 2$
the format would be $(ax - b)(cx - d)$ since the coefficient of $x$ is negative and the constant is $+4$ .

$5(9x^2 - 12x + 4)$
$5(3x - 2)(3x - 2)$
$5(3x - 2)^2$

How do you factor 45x^2 - 60x +20 45x^2 - 60x +20 ?