Question #bee24

1 Answer
radee
Nov 18, 2017

#12i - 5#

Explanation:

#(2 + 3i)^2#

Expand first and treat #i# as if it were a variable
#(2 + 3i)^2#
#4 + 12i + 9i^2#

Since we know that
#i^1 = i#
#i^2 = -1#
#i^3 = -i#
#i^4 = 1#
We can substitute the value of #i^2# with #-1#

#4 + 12i + 9i^2#
#4 + 12i + 9(-1)#
#4 + 12i - 9#
#12i - 5#

Thank you very much to hello for noticing this correction :D

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