Question

How do you evaluate `(12+ 28- 4) \div 6+ 3^ { 2}`?

Answer 1

`15`

Explanation:

Laws:
1) First "()", Second power/sqrtroot, Third times or divided, Forth plus or minus.
2) evaluate from left to right.
3) `x^2=x*x`

---

First:
"()"
`=> (12+28-4)=(40-4)=36`

Second:
"power"
`=> 3^2=3*3=9`

Third:
"divided"
`=> (12+28-4):6=36:6=6`

Forth:
"plus"
`=>(12+28-4):6+3^2=6+9=15`