Question #874fa
1 Answer
Nov 19, 2017
Yes.
Explanation:
#= ( cancelx * cancel((x-1)!) ) / ((x+1) * cancelx * cancel((x-1)!))#
#=1/(x+1)#
Yes.
#= ( cancelx * cancel((x-1)!) ) / ((x+1) * cancelx * cancel((x-1)!))#
#=1/(x+1)#