Question

If `f(x) =-e^(-2x-7)` and `g(x) = 3/x`, what is `f'(g(x))`?

Answer 1

`f'(g(x))=2e^(-6/x-7)`

Explanation:

First thing is to calculate the derivate of `f(x)`,
`f'(x)=2e^(-2x-7)`

and now we substitute `g(x)` in every `x` of the `f'(x)`,
`f'(g(x))=2e^(-2·3/x-7)=2e^(-6/x-7)`