How do you evaluate #(2p ^ { 2} q ) ( 3p q ) ( 4a )#?

1 Answer
Tamir E.
Nov 19, 2017

#24p^3q^3a#

Explanation:

#(color(red)(2)color(blue)(p^2)color(green)(q))(color(red)(3)color(blue)(p)color(green)(q^2))(color(red)(4)a)=(color(red)(2*3*4))(color(blue)(p^2*p))(color(green)(q*q^2))(a)=color(red)(24)color(blue)(p^3)color(green)(q^3)a#

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