How do you simplify #\frac { - 3y ^ { 2} + 27} { y ^ { 2} + 7y + 12}#?

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Answer 1 · 2017-11-20T02:29:27

#(-3(y-3) )/ (y+4)#

Numerator:

#-3(y^2 - 9 )#

#-3(y-3)(y+3)#

Denominator:
factor #y^2 + 7y +12#

#=(y+3)(y+4)#

Together:

#(-3(y-3)(y+3))/((y+3)(y+4)) #

# = (-3(y-3)) / (y+4)#

That #(y+3)#canceled each other. The result would be the answer