How do you simplify $\frac{- 3 y^{2} + 27}{y^{2} + 7 y + 12}$ $\frac { - 3y ^ { 2} + 27} { y ^ { 2} + 7y + 12}$ ?

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Answer 1 · 2017-11-20T02:29:27

$\frac{- 3 (y - 3)}{y + 4}$ $(-3(y-3) )/ (y+4)$

Numerator:

$- 3 (y^{2} - 9)$ $-3(y^2 - 9 )$

$- 3 (y - 3) (y + 3)$ $-3(y-3)(y+3)$

Denominator:
factor $y^{2} + 7 y + 12$ $y^2 + 7y +12$

$= (y + 3) (y + 4)$ $=(y+3)(y+4)$

Together:

$\frac{- 3 (y - 3) (y + 3)}{(y + 3) (y + 4)}$ $(-3(y-3)(y+3))/((y+3)(y+4))$

$= \frac{- 3 (y - 3)}{y + 4}$ $= (-3(y-3)) / (y+4)$

That $(y + 3)$ $(y+3)$ canceled each other. The result would be the answer

How do you simplify −3y2+27y2+7y+12\frac { - 3y ^ { 2} + 27} { y ^ { 2} + 7y + 12}?