Question #dcf48

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Answer 1 · 2017-11-20T04:38:30

True

A full cubic polynomial looks like this:
$f(x)=ax^3+bx^2+cx+d$

Let's write an equation that shows the roots of the function. Two of the roots are 0. Let's assume the third root is $b$ .

$f(x)=x*x*(x-b)$

As you can see, two of the roots are equal to 0 and the other is equal to $b$ .

Let's expand this equation:

$f(x)=x^2*(x-b)$

$f(x)=x^3-bx^2$

We can see that there are no linear ( $cx$ ) or constant ( $d$ ). Therefore, the statement is true. Hope this helps.