A rectangle has sides $x^{2} + 4 x$ $x^2 + 4x$ and $4 x + 12$ $4x+12$ , what is its area?

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Answer 1 · 2017-11-20T06:46:17

The area of the rectangle is $4 x^{3} + 28 x^{2} + 48 x$ $4x^3+28x^2+48x$ units squared.

A rectangle's area is calculated by using the formula: $A = l w$ $A=lw$ . Other variants include $A = b h$ $A=bh$ .

$A = l w$ $A=lw$

$= (x^{2} + 4 x) (4 x + 12)$ $=(x^2+4x)(4x+12)$

At this point, we are now going to foil the equation. This is how you multiply two binomials.

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$= 4 x^{3} + 12 x^{2} + 16 x^{2} + 48 x$ $=4x^3+12x^2+16x^2+48x$

Now we simplify.

$= 4 x^{3} + 28 x^{2} + 48 x$ $=4x^3+28x^2+48x$

Therefore, the area of the rectangle is $4 x^{3} + 28 x^{2} + 48 x$ $4x^3+28x^2+48x$ units squared.

Hope this helps :)

A rectangle has sides x2+4xx^2 + 4x and 4x+124x+12, what is its area?