How do you evaluate #\frac { x } { x ^ { 2} - 9} + \frac { 3} { x ( x - 3) } #?

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Answer 1 · 2017-11-20T06:59:16

#x/(x^2-9) + 3/(x(x-3))=(x^2+3x+9)/(x(x-3)(x+3))#

#x/(x^2-9) + 3/(x(x-3))#

Factorising the denominator of the first fraction:

#=x/((x-3)(x+3)) + 3/(x(x-3))#

Putting fractions together by creating a common denominator:

#=(x(x)+3(x+3))/(x(x-3)(x+3))#

Expanding the numerator:

#=(x^2+3x+9)/(x(x-3)(x+3))#