What is the mass in grams of 1.88 xx10^241.88×1024 molecules "CH"_2"O"CH2O?

1 Answer
Ernest Z. · Denise Granger
Nov 20, 2017

93.7 g

Explanation:

I am going to assume that there are 1.88 * 10^241.88⋅1024 molecules of "CH"_2"O"CH2O

In this case, the go-to formula is

"moles" = "molecules"/"Avogadro's number"moles=moleculesAvogadro's number

"moles" = 1.88 xx 10^24 color(red)(cancel(color(black)("molecules"))) xx "1 mol"/(6.022 xx 10^23 color(red)(cancel(color(black)("molecules")))) = "3.122 mol"

Relative molecular mass is obtained from the P. Table

12.0107 + (2xx1.00794) + 15.9994 = 30.02598

"mass" = 3.122 color(red)(cancel(color(black)("mol"))) xx "30.02598 g"/(1 color(red)(cancel(color(black)("mol")))) = "93.7 g"

Answer: "93.7 g"

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