Question #23502

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Question #23502

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Answer 1 · 2017-11-21T04:39:16

For $10$ $10$ seconds.

Explanation:

The relationship between distance( $d$ $d$ ), speed( $v$ $v$ ) and time ( $t$ $t$ ) is $d = v t$ $d=vt$ .
Therefore, $t = \frac{d}{v}$ $t=d/v$ is the formula you should use in the question.

Since $9.1$ $9.1$ km $= 9100$ $=9100$ m, the time required to finish for driver 1 is $t_{1} = \frac{9100}{65} = 140$ $t_1=9100/65 = 140$ (s). Driver 2 finishes in $t_{2} = \frac{9100}{70} = 130$ $t_2=9100/70=130$ (s).

Driver 2 have to wait $t_{1} - t_{2} = 140 - 130 = 10$ $t_1-t_2=140-130=10$ seconds.

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Question #23502

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