How do you solve 2p^ { 3} - 3p ^ { 2} - 98p + 147= 02p3−3p2−98p+147=0?
2 Answers
Explanation:
factor out
factor out -49 from
factor
Explanation:
"factorise by "color(blue)"grouping"factorise by grouping
2p^3-98p-3p^2+147=02p3−98p−3p2+147=0
rArrcolor(red)(2p)(p^2-49)color(red)(-3)(p^2-49)=0⇒2p(p2−49)−3(p2−49)=0
rArr(p^2-49)(color(red)(2p-3))=0⇒(p2−49)(2p−3)=0
rArr(p-7)(p+7)(2p-3)=0larrcolor(blue)"difference of squares"⇒(p−7)(p+7)(2p−3)=0←difference of squares
"equate each factor to zero and solve for p"equate each factor to zero and solve for p
p-7=0rArrp=7p−7=0⇒p=7
p+7=0rArrp=-7p+7=0⇒p=−7
2p-3=0rArrp=3/22p−3=0⇒p=32