Question

Question #31a86

Answer 1

3,360

Explanation:

Assuming we're doing full anagrams (using all of the letters), we can recognize that there are 8 letters, and so there are 8! ways to arrange all of those letters in a way where the ordering matters.

However, since there's no visual way to distinguish the 3 letter As apart from each other, those letter As can be arranged in 3! ways, all of which will appear to be identical to us. In addition, the two letter Rs can be arranged 2! (or 2) ways as well.

Thus, the number of different anagrams (visually at least) will be:

`(8!)/(3!2!) = (8*7*6*5*4*cancel(3!))/(cancel(3!)2!) = 8*7*6*5*2=3360`