How do you simplify $\frac { 4( x ^- 1) ^- 3} { 4^- 2( x ^- 1) ^- 1}$ ?

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Answer 1 · 2017-11-23T12:15:51

${4(x^(-1))^(-3)}/{4^-2(x^(-1))^(-1)}=64x^2$

AND

$x!=0$

Laws:
$x^a*x^b=x^(a+b)$
$(x^a)^b=x^(a*b)$
$x^-1=1/x$

$f_((x))={4(x^(-1))^(-3)}/{4^-2(x^(-1))^(-1)}=$
$={4^2*4(x^3)}/{(x^1)}=$
$=4^3(x^2)=$
$=64x^2$

How do you simplify \frac { 4( x ^- 1) ^- 3} { 4^- 2( x ^- 1) ^- 1}\frac { 4( x ^- 1) ^- 3} { 4^- 2( x ^- 1) ^- 1}?