How do you simplify #\frac { 4( x ^- 1) ^- 3} { 4^- 2( x ^- 1) ^- 1}#?

1 Answer
Tamir E.
Nov 23, 2017

#{4(x^(-1))^(-3)}/{4^-2(x^(-1))^(-1)}=64x^2#

AND

#x!=0#

Explanation:

Laws:
#x^a*x^b=x^(a+b)#
#(x^a)^b=x^(a*b)#
#x^-1=1/x#

#f_((x))={4(x^(-1))^(-3)}/{4^-2(x^(-1))^(-1)}=#
#={4^2*4(x^3)}/{(x^1)}=#
#=4^3(x^2)=#
#=64x^2#

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