Question #78c95

1 Answer
Nov 24, 2017

The original number is 83.

Explanation:

Let the digit at tenth place be x and at unit place be y.

So, the number in algebraic form is 10x+y.

From the first condition

y=x/2-1=(x-2)/2.......(i)

From second condition

10y+x=3(x+y)+5

or, 10y+x=3x+3y+5

or, 7y=2x+5

Putting the value of y from (i) we get

7((x-2)/2)=2x+5

or, 7x-14=4x+10

or, 3x=24

or, x=24/3=8

Putting the value of x in (i) we get

y=(x-2)/2=(8-2)/2=3

Now 10x+y=10*8+3=83

So the required number is 83.