Question

Question #fc046

Answer 1

`PV = nRT`

`45.3mmHg * (atm)/(760mmHg) * 356mL * L/(10^3mL) = n * (0.08206L*atm)/(mol*K) * 309.7K`
`therefore n_(F_2) approx 8.35*10^-4mol`

As Ernest states, we'll need the mass to "calculate" the molar mass, even though you and I know it's really 38g/mol.