How do you solve #\root[ 3] { x - 6} + 6= - 4#?

Question

913 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-26T20:41:56

#x=-994#

#\root(3)(x-6)+6=-4#

Subtract #6# from both sides:

#\root(color(red)(3))(x-6)=-10#

Cube both sides to cancel out the cube root:

#(\root(color(red)(3))(x-6))^color(red)(3)=(-10)^color(red)(3)#

Simplifying:

#x-6=-1000#

#\rightarrow x=-944#