How can the graph $x^{2}$ $x^2$ be transformed to ${(x + 2)}^{2} - 3$ $(x+2)^2-3$ ?

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Answer 1 · 2017-11-27T05:06:36

Compare $y = {(x + 2)}^{2} - 3$ $y=(x+2)^2-3$ to $y = a f (b (x - h)) + k$ $y=af(b(x-h))+k$

h= -2
k= -3

Compare $y = x^{2}$ $y=x^2$ to $y = {(x + 2)}^{2} - 3$ $y=(x+2)^2-3$

The graph of $y = x^{2}$ $y=x^2$ will transform 2 units left and 3 units down to become $y = {(x + 2)}^{2} - 3$ $y=(x+2)^2-3$
enter image source here

red: $y = x^{2}$ $y=x^2$
blue: $y = {(x + 2)}^{2} - 3$ $y=(x+2)^2-3$

How can the graph x2x^2 be transformed to (x+2)2−3(x+2)^2-3?