Question

What is the value of x? (thanks!)

2x+2=3x-63

Answer 1

`x=65`

Explanation:

`2x+2=3x-63`

Firstly, we can subtract `2x` from both sides of the equation:

`2x+2-2x=3x-63-2x`

Which gives:

`2=x-63`

We can then add `63` to both sides also:

`2+63=x-63+63`

Which gives:

`65=x`

Answer 2

`x=65`

Explanation:

`"collect x terms on one side of the equation and"`
`"numeric values on the other side"`

`"subtract 2x from both sides"`

`cancel(2x)cancel(-2x)+2=3x-2x-63`

`rArr2=x-63`

`"add 63 to both sides"`

`2+63=xcancel(-63)cancel(+63)`

`rArr65=xtox=65`

`color(blue)"As a check"`

Substitute this value into the equation and if both sides are equal then it is the solution.

`"left "=(2xx65)+2=130+2=132`

`"right "=(3xx65)-63=195-63=132`

`rArrx=65" is the solution"`